Question on: JAMB Mathematics - 1991
Find the range of values of x which satisfy the inequality \(\frac{x}{2}\) + \(\frac{x}{3}\) + \(\frac{x}{4}\) < 1
A
x < \(\frac{12}{13}\)
B
x < 13
C
x < 9
D
\(\frac{13}{12}\)
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Correct Option: A
\(\frac{x}{2}\) + \(\frac{x}{3}\) + \(\frac{x}{4}\)< 1
= \(\frac{6x + 4x + 3x < 12}{12}\)
i.e. 13 x < 12 = x < \(\frac{12}{13}\)
= \(\frac{6x + 4x + 3x < 12}{12}\)
i.e. 13 x < 12 = x < \(\frac{12}{13}\)
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